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Answer:6
-90°<θ<0° ===> sinθ<0
sinθ=-√(3²-1²)/3=-√8/3
Solution1:
cosθ/(1+sinθ)+(1+sinθ)/cosθ
=(1/3)/(1-√8/3)+(1-√8/3)/(1/3)
=1/(3-√8)+(3-√8)
=(3+√8)+(3-√8)
=6 Solution2:
=[cos²θ+(1+sinθ)²]/[cosθ*(1+sinθ)]
=(cos²θ+sin²θ+2sinθ+1)/[cosθ*(1+sinθ)]
=(2+2sinθ)/[cosθ*(1+sinθ)]
=[2+2*(-√8/3)]/[(1/3)*(1-√8/3)]
=[2*(1-√8/3)]/[(1/3)*(1-√8/3)]
=2/(1/3)
=2*3
=6 有問題請再提問.
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